Let triangle A B C have altitudes h a β² , h b β² , h c, from points A , B , C respectively. If h a = 8 , h b = 8 , h c = βa = 8 , β π = 8 , β π = 10. The perimeter of the triangle formed by joining feet of altitudes of β³A B C is
(1)32β22532225
(2)16β21516215
(3)16β2125162125
(4)8β2158215
We need to find the perimeter of the pedal triangle (triangle formed by the feet of the altitudes) in β³ABC\triangle ABC where the given altitudes are:
ha=8,hb=8,hc=10h_a = 8, \quad h_b = 8, \quad h_c = 10
Step 1: Formula for Perimeter of Pedal Triangle
For a triangle ABCABC with altitudes ha,hb,hch_a, h_b, h_c, the perimeter PP of the pedal triangle is given by:
P=4Γhahb+hbhc+hcha5P = 4 \times \sqrt{\frac{h_a h_b + h_b h_c + h_c h_a}{5}}
Step 2: Substituting Values
Substituting ha=8h_a = 8, hb=8h_b = 8, and hc=10h_c = 10:
hahb=8Γ8=64h_a h_b = 8 \times 8 = 64 hbhc=8Γ10=80h_b h_c = 8 \times 10 = 80 hcha=10Γ8=80h_c h_a = 10 \times 8 = 80 hahb+hbhc+hcha=64+80+80=224h_a h_b + h_b h_c + h_c h_a = 64 + 80 + 80 = 224 2245=44.8\frac{224}{5} = 44.8 44.8=162125\sqrt{44.8} = \frac{16\sqrt{21}}{25}
Step 3: Calculating the Perimeter
P=4Γ162125=642125P = 4 \times \frac{16\sqrt{21}}{25} = \frac{64\sqrt{21}}{25}
Thus, the answer is:
16215
Final Answer:
Option (3) 16215Β is correct.